x^2+27x+18=0

Solution for x^2+27x+18=0 equation:

x^2+27x+18=0

a = 1; b = 27; c = +18;
Δ = b2-4ac
Δ = 272-4·1·18
Δ = 657
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{657}=\sqrt{9*73}=\sqrt{9}*\sqrt{73}=3\sqrt{73}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-3\sqrt{73}}{2*1}=\frac{-27-3\sqrt{73}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+3\sqrt{73}}{2*1}=\frac{-27+3\sqrt{73}}{2}
$